Q:

Write the equation of the line, in point-slope form. Identify (x1, y1) as the point (-2, -1). Use the box provided or the upload option to submit all of your calculations and final answers.

Accepted Solution

A:
For this case we have that by definition, the equation of a line in the point-slope form is given by:[tex](y-y_ {0}) = m (x-x_ {0})[/tex]Where:[tex](x_ {0}, y_ {0})[/tex]: It is a point through which the line passesm: It's the slopeWe have according to the graph, that the line goes through:[tex](x_ {1}, y_ {1}): (- 2, -1)\\(x_ {2}, y_ {2}) :( 2,1)[/tex]We found the slope:[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {1 - (- 1)} {2 - (- 2)} = \frac {1 +1} {2 + 2} = \frac {2} {4} = \frac {1} {2}[/tex]Thus, the line is of the form:[tex](y-y_ {0}) = \frac {1} {2} (x-x_ {0})[/tex]We substitute a point:[tex](y-1) = \frac {1} {2} (x-2)[/tex]Answer:[tex](y-1) = \frac {1} {2} (x-2)[/tex]